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a(n) = A082249(n)/7.
1

%I #5 May 06 2018 00:43:45

%S 3173145597388,4183246607489,5193347617590,6203448627691,

%T 7213549637792,8223650647893,9233751657994,10243852668095,

%U 11253953678196,12264054688297,13274155698398,14284256708499,15443872300729157586

%N a(n) = A082249(n)/7.

%C Some pattern is visible which would change when numbers of three or more digits occur in A082249. Conjecture: If the concatenation of k consecutive r-digit numbers is divisible by n then the concatenation of the next k numbers would also be divisible by n provided it contains the same number of digits as the first number. This should be true for both forward and reverse concatenation.

%Y Cf. A082242, A082243, A082247, A082248, A082249.

%K base,easy,nonn

%O 1,1

%A _Amarnath Murthy_, Apr 11 2003

%E More terms from Antonio G. Astudillo (afg_astudillo(AT)lycos.com), Apr 19 2003