OFFSET
1,1
COMMENTS
If m and n are the generators of the primitive Pythagorean triples (PPT) with m>n, GCD(m,n)=1 and (m+n) odd then the odd leg is m^2-n^2 and the even leg is 2m*n. Therefore the even leg is shortest if 2m*n<m^2-n^2, i.e., m>(1+sqrt(2))*n. Also this is a sequence of numbers whose square is the semiperimeter of a PPT. - Frank M Jackson, Oct 10 2014
LINKS
Ray Chandler, Table of n, a(n) for n = 1..10000 (first 1621 terms from Vincenzo Librandi)
MATHEMATICA
lst1 = {}; Do[If[GCD[m, n]==1&&m(Sqrt[2]+1)<n&&OddQ[m+n], AppendTo[lst1, n(m+n)]], {n, 1, 100}, {m, 1, n}]; Sort@lst1 (* Frank M Jackson, Oct 10 2014 *)
CROSSREFS
KEYWORD
nonn
AUTHOR
Lekraj Beedassy, Apr 23 2003
EXTENSIONS
More terms from Ray Chandler, Oct 29 2003
STATUS
approved