OFFSET
0,2
COMMENTS
Binomial transform of A081911 6th binomial transform of (1,0,1,0,0,0,...). Case k=6 where a(n,k) = k^n*(n^2 - n + 2k^2)/(2k^2) with g.f. (1 - 2kx + (k^2+1)x^2)/(1-kx)^3.
LINKS
Vincenzo Librandi, Table of n, a(n) for n = 0..150
Index entries for linear recurrences with constant coefficients, signature (18,-108,216).
FORMULA
a(n) = 6^n*(n^2 - n + 72)/72.
G.f.: (1 - 12x + 37x^2)/(1-6x)^3.
PROG
(Magma) [6^n*(n^2-n+72)/72: n in [0..40]]; // Vincenzo Librandi, Apr 27 2011
CROSSREFS
KEYWORD
easy,nonn
AUTHOR
Paul Barry, Mar 31 2003
STATUS
approved