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A081887
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Numbers k such that lcm(1..k) equals the denominator of the sum of the first k harmonic numbers.
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0
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1, 2, 4, 10, 12, 16, 28, 30, 52, 88, 96, 126, 130, 136, 138, 148, 150, 250, 256, 262, 268, 270, 292, 970, 976, 982, 990, 996, 1008, 1012, 1018, 1020, 1030, 1032, 1038, 1048, 1050, 1060, 1062, 1372, 1380, 1398, 1408, 1422, 1426, 1428, 1432, 1438
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OFFSET
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1,2
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COMMENTS
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k+1 must be a prime, but converse is not true.
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LINKS
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EXAMPLE
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The sum of the first 4 harmonic numbers is 77/12 and 12 is lcm(1,2,3,4).
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MATHEMATICA
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big=Table[LCM @@Range[n]/Denominator[ -n+(1+n) HarmonicNumber[n]], {n, 2048}]; Position[big, 1]//Flatten
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PROG
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(PARI) h(n) = sum(j=1, n, 1/j);
isok(n) = lcm(vector(n, k, k)) == denominator(sum(k=1, n, h(k))); \\ Michel Marcus, Mar 15 2018
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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