
COMMENTS

In other words, a(n) is the smallest number m such that m has n distinct divisors d_1, ..., d_n such that d_1+...+d_n = m. (The d_i do not need to be ALL the divisors of m.) For example, a(6) = m = 24, since the divisors of 24 are 1,2,3,4,6,8,12,24, and 1+2+3+4+6+8=24.
In the following triangle the nth row gives examples of the n divisors a(1), ..., a(7); a(n) = sum of the nth row:
1
 
1 2 3
1 2 3 6
1 2 3 6 12
1 2 3 4 6 8
1 2 3 6 8 12 16
For a given values of a(n) = m, however, there may be more than one way to choose d_1, ..., d_n so that d_1+...+d_n = m.
For n=10, a(10)=120, for example, there are the following equally valid solutions:
[1, 2, 3, 4, 5, 6, 15, 20, 24, 40]
[1, 2, 3, 4, 5, 8, 10, 12, 15, 60]
[1, 2, 3, 4, 5, 8, 12, 15, 30, 40]
[1, 2, 3, 4, 6, 8, 12, 20, 24, 40]
[1, 2, 3, 5, 6, 8, 10, 15, 30, 40]
[1, 2, 3, 5, 8, 10, 12, 15, 24, 40]
[1, 2, 3, 5, 8, 12, 15, 20, 24, 30]
[1, 2, 4, 5, 6, 8, 10, 20, 24, 40]
[1, 2, 4, 6, 8, 10, 15, 20, 24, 30]
[1, 3, 4, 5, 6, 10, 12, 15, 24, 40]
[1, 3, 4, 5, 6, 12, 15, 20, 24, 30]
[1, 3, 4, 5, 8, 10, 15, 20, 24, 30]
[1, 3, 5, 6, 8, 10, 12, 15, 20, 40]
[1, 4, 5, 6, 8, 10, 12, 20, 24, 30]
[2, 3, 4, 5, 6, 8, 10, 12, 30, 40]
[2, 3, 4, 6, 8, 10, 12, 15, 20, 40]
[2, 3, 5, 6, 8, 10, 12, 20, 24, 30]
(These solutions were provided by Jinyuan Wang.)
The lexicographically earliest solution is given as the nth row of the triangle in A081514. The corresponding value d_n is given in A081513.
The lexicographically earliest solutions are:
..n....m: d_1 d_2 ... d_n

..1....1: 1
..2....0:  
..3....6: 1, 2, 3
..4...12: 1, 2, 3, 6
..5...24: 1, 2, 3, 6, 12
..6...24: 1, 2, 3, 4, 6, 8
..7...48: 1, 2, 3, 4, 6, 8, 24
..8...60: 1, 2, 3, 4, 5, 10, 15, 20
..9...84: 1, 2, 3, 4, 6, 7, 12, 21, 28
.10..120: 1, 2, 3, 4, 5, 6, 15, 20, 24, 40
...
