login
Define b by b(1) = 1 and for n>1, b(n) = b(n-1)+1/(2+1/b(n-1)); sequence gives denominator of b(n).
3

%I #8 Apr 09 2014 10:13:01

%S 1,3,33,4785,118289985,83574429584465985,

%T 47533348097639173195113266868291585,

%U 17303590888755815609063515462865866934559547198082397287546077959536385

%N Define b by b(1) = 1 and for n>1, b(n) = b(n-1)+1/(2+1/b(n-1)); sequence gives denominator of b(n).

%C Suggested by _Leroy Quet_, Feb 26 2003.

%F See under A080984.

%e See under A080984.

%o Reduce: See under A080984.

%Y Cf. A080984, A080986, A080987, A079269, A079278.

%K frac,nonn

%O 1,2

%A _Hugo Pfoertner_, Feb 26 2003