%I #6 Mar 30 2012 18:39:16
%S 1,1,2,3,5,8,13,21,24,25,29,34,43,47,50,57,57,64,71,75,76,81,87,88,95,
%T 103,108,111,119,120,129,129,138,147,155,162,167,169,176,185,191,196,
%U 197,203,210,213,213,216,219,225,234,239,243,252,255,257,262,269,271
%N a(1)=a(2)=1; a(n) = a(n-1) + last decimal digit of a(n-2).
%F a(n)=a(n-1)+a(n-2)(mod 10); for n>=3 a(n)-a(n-1)=A003893(n-2)=A000045(n-2)(mod 10)
%K base,nonn
%O 1,3
%A _Benoit Cloitre_, Mar 12 2003