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a(1)=a(2)=1; a(n) = a(n-1) + last decimal digit of a(n-2).
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%I #6 Mar 30 2012 18:39:16

%S 1,1,2,3,5,8,13,21,24,25,29,34,43,47,50,57,57,64,71,75,76,81,87,88,95,

%T 103,108,111,119,120,129,129,138,147,155,162,167,169,176,185,191,196,

%U 197,203,210,213,213,216,219,225,234,239,243,252,255,257,262,269,271

%N a(1)=a(2)=1; a(n) = a(n-1) + last decimal digit of a(n-2).

%F a(n)=a(n-1)+a(n-2)(mod 10); for n>=3 a(n)-a(n-1)=A003893(n-2)=A000045(n-2)(mod 10)

%K base,nonn

%O 1,3

%A _Benoit Cloitre_, Mar 12 2003