OFFSET
0,2
COMMENTS
Original puzzle was to find the next four terms after 2, 3, 8, 27, 125. The cubes were intended to mislead - providing one further term would have made the intended sequence too obvious.
REFERENCES
Cambridge Archimedeans' Problems Drive, 2001.
LINKS
Vincenzo Librandi, Table of n, a(n) for n = 0..100
FORMULA
E.g.f.: (2/sqrt(5))*exp(x/2)*sinh(sqrt(5)*x/2)+1/(1-x). - Alois P. Heinz, Jul 05 2015
MAPLE
with(combstruct): with(combinat): a:=proc(m) [ZL, {ZL=Set(Cycle(Z, card>=m))}, labeled]; end: ZLL:=a(1): seq(count(ZLL, size=n)+fibonacci(n), n=0..19); # Zerinvary Lajos, Jun 11 2008
MATHEMATICA
Table[n!+Fibonacci[n], {n, 0, 100}] (* Vladimir Joseph Stephan Orlovsky, May 02 2011 *)
PROG
(Magma) [Factorial(n)+Fibonacci(n): n in [0..25]]; // Vincenzo Librandi, May 03 2011
(PARI) vector(30, n, n--; n! + fibonacci(n)) \\ Michel Marcus, Jul 05 2015
CROSSREFS
KEYWORD
easy,nonn
AUTHOR
Alasdair Kergon (agk(AT)oxlug.org), Feb 21 2003
STATUS
approved