OFFSET
1,2
PROG
(Python)
def a(n):
s = "".join(sorted("".join(map(str, range((n-1)*n//2+1, n*(n+1)//2+1)))))
if '0' not in s: return int(s)
rz = s.rfind('0')
return int(s[rz+1] + s[:rz+1] + s[rz+2:])
print([a(n) for n in range(1, 15)]) # Michael S. Branicky, Jan 23 2021
CROSSREFS
KEYWORD
base,easy,nonn
AUTHOR
Amarnath Murthy, Mar 11 2003
EXTENSIONS
More terms from Antonio G. Astudillo (afg_astudillo(AT)lycos.com), Apr 19 2003
STATUS
approved