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Let s(1) = 1; let s(2m) = {s(2m-1),m+1,s(2m-1)}, s(2m+1) = {s(2m),s(2m)}; sequence gives limit of s(k) for large k.
1

%I #6 Mar 11 2014 01:32:12

%S 1,2,1,1,2,1,3,1,2,1,1,2,1,1,2,1,1,2,1,3,1,2,1,1,2,1,4,1,2,1,1,2,1,3,

%T 1,2,1,1,2,1,1,2,1,1,2,1,3,1,2,1,1,2,1,1,2,1,1,2,1,3,1,2,1,1,2,1,1,2,

%U 1,1,2,1,3,1,2,1,1,2,1,4,1,2,1,1,2,1,3,1,2,1,1,2,1,1,2,1,1,2,1

%N Let s(1) = 1; let s(2m) = {s(2m-1),m+1,s(2m-1)}, s(2m+1) = {s(2m),s(2m)}; sequence gives limit of s(k) for large k.

%Y Cf. A080028.

%K nonn,easy

%O 1,2

%A _Leroy Quet_, Feb 07 2003