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A079707
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In prime factorization of n replace odd primes with their prime predecessor.
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1
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1, 2, 2, 4, 3, 4, 5, 8, 4, 6, 7, 8, 11, 10, 6, 16, 13, 8, 17, 12, 10, 14, 19, 16, 9, 22, 8, 20, 23, 12, 29, 32, 14, 26, 15, 16, 31, 34, 22, 24, 37, 20, 41, 28, 12, 38, 43, 32, 25, 18, 26, 44, 47, 16, 21, 40, 34, 46, 53, 24, 59, 58, 20, 64, 33, 28, 61, 52, 38, 30, 67, 32, 71, 62, 18
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OFFSET
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1,2
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COMMENTS
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LINKS
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FORMULA
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a(n) <= n; a(n) < n iff n > 1 is odd; a(n) = n iff n = 2^k.
For 3-smooth numbers: a(2^i * 3^j) = 2^(i+j).
Multiplicative with 2->2 and prime(k)->prime(k-1), k>1.
Sum_{k=1..n} a(k) ~ c * n^2, where c = (1/2) * Product_{p prime > 2} ((p^2-p)/(p^2 - prevprime(p))) = 0.3310558934..., where prevprime is A151799. - Amiram Eldar, Nov 29 2022
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MATHEMATICA
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f[p_, e_] := If[p == 2, 2, NextPrime[p, -1]]^e; a[1] = 1; a[n_] := Times @@ f @@@ FactorInteger[n]; Array[a, 100] (* Amiram Eldar, Nov 29 2022 *)
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PROG
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(PARI) a(n) = {my(f = factor(n)); prod(i = 1, #f~, if(f[i, 1] == 2, f[i, 1], precprime(f[i, 1]-1))^f[i, 2]); } \\ Amiram Eldar, Nov 29 2022
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CROSSREFS
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KEYWORD
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nonn,easy,mult
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AUTHOR
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STATUS
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approved
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