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A079613 a(n) = F(3*2^n) where F(k) denotes the k-th Fibonacci number. 4
2, 8, 144, 46368, 4807526976, 51680708854858323072, 5972304273877744135569338397692020533504, 79757008057644623350300078764807923712509139103039448418553259155159833079730688 (list; graph; refs; listen; history; text; internal format)
OFFSET
0,1
COMMENTS
Let b = sqrt(5)/5. We have the alternating series identity (10 - 4*sqrt(5))/5 = b/2 - b^2/(2*8) + b^3/(2*8*144) - b^4/(2*8*144*46368) + ..., so this sequence is a generalized Pierce expansion of (10 - 4*sqrt(5))/5 to the base b as defined in A058635. - Peter Bala, Nov 04 2013
REFERENCES
Ronald L. Graham, Donald E. Knuth and Oren Patashnik, Concrete mathematics, second edition, Addison Wesley, 1994, p. 557, ex. 6.61.
LINKS
V. E. Hoggatt, Jr. and Marjorie Bicknell, A Reciprocal Series of Fibonacci Numbers with Subscripts 2^n k, The Fibonacci Quarterly, Vol. 14, No. 5 (1976), p. 453-455.
FORMULA
Sum_{n>=0} 1/a(n) = 5/4 - 1/phi = 0.6319660112... since Sum_{k=0..n} 1/a(k) = 5/4 - F(3*2^n-1)/F(3*2^n).
a(n) = A081976(n+1)*A081976(n+2). - Amarnath Murthy, Apr 03 2003
a(n) = (1/sqrt(5))*( (2 + sqrt(5))^2^n - 1/(2 + sqrt(5))^2^n ) for n >= 1. - Peter Bala, Nov 04 2013
a(n) = A000045(A007283(n)). - Amiram Eldar, Jan 29 2022
MATHEMATICA
Table[Fibonacci[3*2^n], {n, 0, 7}] (* Amiram Eldar, Jan 29 2022 *)
PROG
(Magma) [Fibonacci(3*2^n) : n in [0..7]]; // Wesley Ivan Hurt, Apr 05 2023
CROSSREFS
Sequence in context: A166356 A009817 A124105 * A091299 A362729 A307326
KEYWORD
nonn
AUTHOR
Benoit Cloitre, Jan 29 2003
STATUS
approved

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Last modified April 23 02:53 EDT 2024. Contains 371906 sequences. (Running on oeis4.)