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A079278
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Define b by b(1) = 1 and for n>1, b(n) = b(n-1)+1/(1+1/b(n-1)); sequence gives denominator of b(n).
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6
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OFFSET
| 1,2
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REFERENCES
| Suggested by Leroy Quet Feb 14 2003.
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FORMULA
| Conjecture (Quet): a(m+1) = a(m)^2 + a(m)^3 /a(m-1)^2 - a(m)a(m-1)^2 for m >= 2.
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EXAMPLE
| The b sequence begins 1, 3/2, 21/10, 861/310, 1275141/363010, 2551762438701/594665194510, ...
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MAPLE
| b := proc(n) option remember; if n=1 then 1 else b(n-1)+1/(1+1/b(n-1)); fi; end;
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CROSSREFS
| Cf. A079269, A080581, A080582.
Sequence in context: A073834 A111837 A092123 * A015178 A206152 A013034
Adjacent sequences: A079275 A079276 A079277 * A079279 A079280 A079281
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KEYWORD
| nonn,frac
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AUTHOR
| N. J. A. Sloane (njas(AT)research.att.com), Feb 16 2003
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EXTENSIONS
| The next term is too large to include.
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