%I #3 May 10 2013 12:45:09
%S 0,0,1,1,3,4,6,7,11,13,15,20,21,27,32,35,36,50,45,59,62,70,66,92,81,
%T 99,102,119,105,150,120,155,152,172,162,219,171,216,212,255,210,296,
%U 231,302,295,319,276,396,306,391,362,425,351,492,396,503,452,511,435,646
%N Sum of p in all pairs (p,q), 0<=p<q, p+q divides n.
%F G.f.: Sum_{n>1} x^(3*n)/(1-x^n)/(1-x^(2*n))^2.
%e There are 7 pairs (p,q), 0<=p<q, such that p+q divides 6: (0,1), (0,2), (0,3), (0,6), (1, 2), (1, 5), (2, 4); thus a(6) = 0+0+0+0+1+1+2=4.
%Y Cf. A008805.
%K easy,nonn
%O 1,5
%A _Vladeta Jovovic_, Feb 03 2003