%I #17 Aug 12 2013 13:48:05
%S 0,2,4,6,8,12,18,24,30,36,42,48,54,60,66,72,78,84,90,96,100,130,160,
%T 190,200,230,260,290,300,330,360,390,400,430,460,490,500,530,560,590,
%U 600,630,660,690,700,730,760,790,800,830,860,890,900,930,960,990,1190,1260
%N Numbers n in which the last k digits of n form an integer divisible by the k-th prime, for k = 1, 2, ..., m, where m is the number of digits in n.
%C There are 224 terms in the sequence and 9-digit number 904719030 is the largest number to satisfy the requirements. - _Shyam Sunder Gupta_, Aug 07 2013
%H Shyam Sunder Gupta, <a href="/A079212/b079212.txt">Table of n, a(n) for n = 1..224</a>
%e a(205)=8392730 because 0 is divisible by the first prime 2, 30 by the second prime 3, 730 by the third prime 5 and 2730 by the fourth prime 7, 92730 by the fifth prime 11, 392730 by the sixth prime 13, 8392730 by the seventh prime 17.
%K base,fini,full,nonn
%O 1,2
%A Sudipta Das (juitech(AT)vsnl.net), Feb 03 2003
%E Prepended a(0)=0, _Shyam Sunder Gupta_, Aug 07 2013