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%I #13 Jan 01 2024 13:31:50
%S 1,3,8,24,71,207,603,1755,5109,14871,43290,126034,366964,1068555,
%T 3111755,9062483,26394933,76881876,223952645,652403269,1900652886,
%U 5537521144,16134412398,47012725228,136994031518,399219097098
%N a(n+1) = floor((1/n)*(Sum_{k=1..n} a(k)^((n+1)/k))), given a(0)=1, a(1)=3, a(2)=8.
%H Robert Israel, <a href="/A079121/b079121.txt">Table of n, a(n) for n = 0..400</a>
%e a(4)=71 since 71 = floor((1/3)*(3^(4/1) + 8^(4/2) + 24^(4/3))).
%p A[0]:= 1:
%p A[1]:= 3:
%p A[2]:= 8:
%p for n from 2 to 99 do
%p A[n+1]:= floor(1/n*add(A[k]^((n+1)/k),k=1..n));
%p od:
%p seq(A[i],i=0..100); # _Robert Israel_, Sep 05 2018
%Y Cf. A079116 - A079120.
%K nonn
%O 0,2
%A _Paul D. Hanna_, Dec 27 2002
%E Definition corrected by _Robert Israel_, Sep 05 2018
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