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A079118 a(n) = floor[(1/n) sum_{k=1..n} a(k)^(n/k)], given a(0)=1, a(1)=2, a(2)=6. 0

%I #3 Mar 30 2012 18:36:33

%S 1,2,6,11,25,57,130,297,678,1548,3537,8089,18513,42401,97180,222886,

%T 511541,1174805,2699825,6208514,14286332,32895382,75793307,174747004,

%U 403156146,930729690,2150121210,4970430222,11497923316,26615954928

%N a(n) = floor[(1/n) sum_{k=1..n} a(k)^(n/k)], given a(0)=1, a(1)=2, a(2)=6.

%e a(4)=25 since 25 = floor[(1/3){2^(4/1) + 6^(4/2) + 11^(4/3)}].

%Y Cf. A079116 - A079121.

%K nonn

%O 0,2

%A _Paul D. Hanna_, Dec 27 2002

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Last modified March 29 04:23 EDT 2024. Contains 371264 sequences. (Running on oeis4.)