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%I #10 Nov 21 2013 12:47:56
%S 1,3,1,1,11,1,1,19,1,1,27,1,1,35,1,1,43,1,1,51,1,1,59,1,1,67,1,1,75,1,
%T 1,83,1,1,91,1,1,99,1,1,107,1,1,115,1,1,123,1,1,131,1,1,139,1,1,147,1,
%U 1,155,1,1,163,1,1,171,1,1,179,1,1,187
%N Continued fraction expansion of e^(1/4).
%H G. Xiao, <a href="http://wims.unice.fr/~wims/en_tool~number~contfrac.en.html">Contfrac</a>
%H K. Matthews, <a href="http://www.numbertheory.org/php/davison.html">Finding the continued fraction of e^(l/m)</a>
%F a(4k+2) = 8k+3, otherwise a(i) = 1.
%F G.f.: (6x^4+2x)/(1-x^3)^2+1/(1-x). - _Ralf Stephan_, Mar 13 2003
%t ContinuedFraction[E^(1/4),80] (* _Harvey P. Dale_, Nov 19 2011 *)
%Y Cf. A017101, A058281.
%K cofr,nonn
%O 0,2
%A _Benoit Cloitre_, Dec 17 2002
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