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A078339
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Let u(1)=u(2)=u(3)=1 and u(n)=(-1)^n*sign(u(n-1)-u(n-2))*u(n-3); then a(n)=sum(k=1,n,sum(i=1,k,u(i))) - 3*(n-1).
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0
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1, 0, 0, 0, 1, 3, 5, 6, 8, 10, 11, 11, 11, 10, 8, 6, 5, 3, 1, 0, 0, 0, 1, 3, 5, 6, 8, 10, 11, 11, 11, 10, 8, 6, 5, 3, 1, 0, 0, 0, 1, 3, 5, 6, 8, 10, 11, 11, 11, 10, 8, 6, 5, 3, 1, 0, 0, 0, 1, 3, 5, 6, 8, 10, 11, 11, 11, 10, 8, 6, 5, 3, 1, 0, 0, 0, 1, 3, 5, 6, 8, 10, 11, 11, 11, 10, 8, 6, 5, 3, 1
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OFFSET
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1,6
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COMMENTS
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Note the palindromic form of the periodic part: 0,0,1,3,5,6,8,10,11,11,11,10,8,6,5,3,1,0,0.
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LINKS
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Index entries for linear recurrences with constant coefficients, signature (1, 0, 0, 0, 0, 0, 0, 0, -1, 1).
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FORMULA
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Periodic with period 18.
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MATHEMATICA
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LinearRecurrence[{1, 0, 0, 0, 0, 0, 0, 0, -1, 1}, {1, 0, 0, 0, 1, 3, 5, 6, 8, 10}, 91] (* Ray Chandler, Aug 27 2015 *)
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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