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A078254 Triangular numbers in which alternate digits are equal. 0
0, 1, 3, 6, 10, 15, 21, 28, 36, 45, 55, 66, 78, 91, 171, 595, 666, 5050, 5151 (list; graph; refs; listen; history; text; internal format)
OFFSET
1,3
COMMENTS
No other terms found up to A000217(30000). - Michel Marcus, Sep 17 2013
Numbers in which alternate digits are equal have one of two forms: b*(100^n-1)/99 or b*(100^n-1)/99*10+floor(b/10), where 0<=b<=99. These numbers are triangular if 8*b*(100^n-1)/99+1=y^2 and 8*(b*(100^n-1)/99*10+floor(b/10))+1=y^2, respectively. These equations can be reduced to search of integral points on a finite number of the elliptic curves: 8*b*(100^k*x^3-1)/99+1=y^2 and 8*(b*(100^k*x^3-1)/99*10+floor(b/10))+1=y^2, where x=100^floor(n/3) and k=0, 1, or 2. Each of them has a finite number of integral points and hence there is a finite number of terms in this sequence. - Max Alekseyev, Apr 26 2015
LINKS
CROSSREFS
Sequence in context: A069697 A069699 A213516 * A069700 A069698 A069696
KEYWORD
nonn,base,fini,more
AUTHOR
Amarnath Murthy, Nov 24 2002
STATUS
approved

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Last modified April 23 03:30 EDT 2024. Contains 371906 sequences. (Running on oeis4.)