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A078117
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Let u(1)=n, u(2)=n+1, v(1)=n+2, v(2)=n+3, u(k)=abs(u(k-1)-v(k-2)), v(k)=abs(v(k-1)-u(k-2)), then a(n) is the smallest integer such that for any k>=a(n), v(k)=u(k).
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0
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8, 11, 15, 17, 15, 11, 12, 14, 12, 14, 9, 14, 12, 17, 21, 23, 21, 16, 18, 20, 18, 20, 15, 20, 18, 23, 27, 29, 27, 22, 24, 26, 24, 26, 21, 26, 24, 29, 33, 35, 33, 28, 30, 32, 30, 32, 27, 32, 30, 35, 39, 41, 39, 34, 36, 38, 36, 38, 33, 38, 36, 41, 45, 47, 45, 40, 42, 44, 39, 44
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OFFSET
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1,1
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LINKS
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FORMULA
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a(n)/n -> 1/2; for n>= 7, a(n) = (1/2)*(n+b(n)) where b(n) is the 12-periodic sequence (17, 20, 15, 18, 7, 16, 11, 20, 27, 30, 25, 14)
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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