A078109 Let u(1)=u(2)=1, u(3)=2n, u(k) = abs(u(k-1)-u(k-2)-u(k-3)) and M(k)= Max( u(i) : 1<=i<=k), then for any k>=a(n), M(k)=sqrtint(k + A078108(n)) where sqrtint(x) denotes floor(sqrt(x)).

3, 10, 38, 10, 35, 66, 19, 150, 90, 30, 243, 159, 138, 270, 19, 186, 35, 178, 358, 127, 46, 334, 1, 23, 370, 438, 343, 182, 430, 46, 454, 470, 534, 30, 618, 734, 903, 570, 302, 571, 638, 30, 166, 822

Offset

1,1

Comments

Conjecture : a(n) always exists, a(n)/n^2 is bounded. If initial conditions are u(1)=u(2)=1, u(3)=2n+1, then u(k) reaches a 2-cycle for any k>m large enough (cf. A078098)

Links

Table of n, a(n) for n=1..44.

Crossrefs

Cf. A000196, A078108, A077623.

Sequence in context: A123636 A371901 A092816 * A149045 A149046 A149047

Adjacent sequences: A078106 A078107 A078108 * A078110 A078111 A078112

Keyword

nonn

Author

Benoit Cloitre, Dec 05 2002

Status

approved