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A078033
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Expansion of (1-x) / (1+x^2+2*x^3).
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1
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1, -1, -1, -1, 3, 3, -1, -9, -5, 11, 23, -1, -45, -45, 47, 135, 43, -229, -313, 143, 771, 483, -1057, -2025, 91, 4139, 3959, -4321, -12237, -3597, 20879, 28071, -13685, -69829, -42457, 97199, 182115, -12285, -376513, -351945, 401083, 1104971, 302807, -1907137, -2512749, 1301523, 6327023
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OFFSET
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0,5
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LINKS
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FORMULA
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a(n) = -a(n-2) - 2*a(n-3) for n>2. - Colin Barker, May 18 2019
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MAPLE
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seq(coeff(series((1-x)/((1+x)*(1-x+2*x^2)), x, n+1), x, n), n = 0..40); # G. C. Greubel, Nov 22 2019
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MATHEMATICA
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LinearRecurrence[{0, -1, -2}, {1, -1, -1}, 40] (* G. C. Greubel, Nov 22 2019 *)
CoefficientList[Series[(1-x)/(1+x^2+2x^3), {x, 0, 60}], x] (* Harvey P. Dale, Mar 31 2023 *)
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PROG
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(PARI) Vec((1-x)/((1+x)*(1-x+2*x^2)) + O(x^40)) \\ Colin Barker, May 18 2019
(Magma) R<x>:=PowerSeriesRing(Integers(), 40); Coefficients(R!( (1-x)/((1+x)*(1-x+2*x^2)) )); // G. C. Greubel, Nov 22 2019
(Sage)
P.<x> = PowerSeriesRing(ZZ, prec)
return P( (1-x)/((1+x)*(1-x+2*x^2)) ).list()
(GAP) a:=[1, -1, -1];; for n in [4..40] do a[n]:=-a[n-2]-2*a[n-3]; od; a; # G. C. Greubel, Nov 22 2019
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CROSSREFS
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KEYWORD
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sign,easy
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AUTHOR
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STATUS
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approved
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