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A077999
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Expansion of (1-x)/(1-2*x-2*x^3).
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2
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1, 1, 2, 6, 14, 32, 76, 180, 424, 1000, 2360, 5568, 13136, 30992, 73120, 172512, 407008, 960256, 2265536, 5345088, 12610688, 29752448, 70195072, 165611520, 390727936, 921846016, 2174915072, 5131286016, 12106264064, 28562358272, 67387288576, 158987105280
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OFFSET
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0,3
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COMMENTS
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a(n) = number of permutations on [n] that avoid nonconsecutive instances of the patterns 321 and 312. For example, a(4) does not count pi=4231 because 431 forms a 321 pattern in pi but 431 is not a consecutive (that is, contiguous) string in pi; also, the first 3 letters form a 312 pattern but that's not disqualifying because they do occur consecutively. Counting these permutations by various statistics yields the listed formulas/recurrences. - David Callan, Oct 26 2006
a(n) = term (1,1) of M^n, M = the 4 X 4 matrix [1,0,1,1; 1,1,0,0; 0,1,0,1; 1,0,0,1]. a(n)/a(n-1) tends to 2.3593040859..., an eigenvalue of the matrix and a root to the characteristic polynomial x^4 - 3x^3 + 2x^2 - 2x + 2. - Gary W. Adamson, Oct 01 2008
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LINKS
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FORMULA
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a(n) = 2*(a(n-1) + a(n-3)) counts the above permutations by first entry. a(n) = a(n-1) + a(n-2) + 3*Sum_{k=0..n-3} a(k) counts by last entry. a(n) = 2^(n-1) + Sum_{k=0..n-3} 2^(n-2-k)*a(k) counts by location of first 3xx pattern. a(n) = Sum_{k=0..floor(n/3)} ((n-k)/(n-2k))* binomial(n-2*k,k) * 2^(n-2*k-1) counts by number of 3xx patterns. - David Callan, Oct 26 2006
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MATHEMATICA
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CoefficientList[Series[(1-x)/(1-2x-2x^3), {x, 0, 40}], x] (* or *) LinearRecurrence[{2, 0, 2}, {1, 1, 2}, 40] (* Harvey P. Dale, Sep 10 2016 *)
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PROG
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(PARI) my(x='x+O('x^40)); Vec((1-x)/(1-2*x-2*x^3)) \\ G. C. Greubel, Jun 27 2019
(Magma) R<x>:=PowerSeriesRing(Integers(), 40); Coefficients(R!( (1-x)/( 1-2*x-2*x^3) )); // G. C. Greubel, Jun 27 2019
(Sage) ((1-x)/(1-2*x-2*x^3)).series(x, 40).coefficients(x, sparse=False) # G. C. Greubel, Jun 27 2019
(GAP) a:=[1, 1, 2];; for n in [4..40] do a[n]:=2*(a[n-1]+a[n-3]); od; a; # G. C. Greubel, Jun 27 2019
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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STATUS
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approved
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