%I #5 Dec 05 2013 19:55:56
%S 1,2,34,5678910111213141516171819202122232
%N Partition the digits of the concatenation 123456789101112131415... of natural numbers such that a(n) contains a(n-1) digits with a(1) = 1.
%C Next term is too large to include. - _Sascha Kurz_, Jan 04 2003
%Y Cf. A077748.
%K base,nonn
%O 1,2
%A _Amarnath Murthy_, Nov 20 2002