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a(1) = 3, then a(n) = smallest multiple of the previous term with as many divisors.
1

%I #5 Dec 05 2013 19:55:47

%S 3,9,36,1260,908107200,43468142423564473939246248742562061499584000000

%N a(1) = 3, then a(n) = smallest multiple of the previous term with as many divisors.

%e a(2) = 9 tau(9) = 3, a(3) = 36 tau(36) = 9 etc.

%K nonn

%O 0,1

%A _Amarnath Murthy_, Oct 21 2002

%E Corrected and extended by _Sascha Kurz_, Jan 22 2003