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A076785
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Let u(1)=u(2)=u(3)=1, u(n)=(2^floor(u(n-1)/2)+2^floor(u(n-2)/2)+1)/u(n-3) then a(n) = denominator of u(n).
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1
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1, 1, 1, 1, 1, 1, 3, 4, 1, 13, 13, 1, 3, 12, 3, 1, 13, 13, 1, 4, 3, 1, 1, 1, 1, 1, 1, 1, 1, 1, 3, 4, 1, 13, 13, 1, 3, 12, 3, 1, 13, 13, 1, 4, 3, 1, 1, 1, 1, 1, 1, 1, 1, 1, 3, 4, 1, 13, 13, 1, 3, 12, 3, 1, 13, 13, 1, 4, 3, 1, 1, 1, 1, 1, 1, 1, 1, 1, 3, 4, 1, 13, 13, 1, 3, 12, 3, 1, 13, 13, 1, 4, 3, 1
(list; graph; refs; listen; history; internal format)
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OFFSET
| 1,7
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COMMENTS
| Sequence is 24-periodic
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FORMULA
| Period is (1, 1, 1, 1, 1, 1, 3, 4, 1, 13, 13, 1, 3, 12, 3, 1, 13, 13, 1, 4, 3, 1, 1, 1)
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CROSSREFS
| Cf. A076784.
Sequence in context: A154602 A109956 A123319 * A110506 A114189 A200659
Adjacent sequences: A076782 A076783 A076784 * A076786 A076787 A076788
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KEYWORD
| frac,nonn
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AUTHOR
| Benoit Cloitre (benoit7848c(AT)orange.fr), Nov 24 2002
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