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A076483
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a(n) = n!*Sum_{k=1..n} (k-1)^k/k!.
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3
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0, 0, 1, 11, 125, 1649, 25519, 458569, 9433353, 219117905, 5677963451, 162457597961, 5087919552253, 173136159558361, 6361282619516343, 250987334850557369, 10584205713321808529, 475079402305823570849, 22614513693572549266291, 1137911105533216112417161
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OFFSET
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0,4
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COMMENTS
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Perhaps the largest possible number of ways of choosing (v1, v2, ..., vn), possibly with repetition, from {b1, b2, ..., bn} with b1 < b2 < ... < bn, such that v1 + v2 + ... + vn < b1 + b2 + ... + bn. Clearly the actual number of ways depends on the particular values of {b1, b2, ..., bn}, but {1, n, n^2, ..., n^(n-1)} produces this result for the number of sums strictly less than (n^n-1)/(n-1) = A023037(n).
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LINKS
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FORMULA
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Limit_{n->oo} a(n)/(e*a(n-1)) - n = -1/2.
Limit_{n->oo} a(n)/n^n = 1/(e-1).
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EXAMPLE
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a(4) = 4!*(0^1/1! + 1^2/2! + 2^3/3! + 3^4/4!) = 0 + 12 + 32 + 81 = 125.
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MATHEMATICA
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Table[n! Sum[(k-1)^k/k!, {k, n}], {n, 0, 17}] (* Stefano Spezia, Sep 11 2022 *)
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PROG
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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