login
a(n) = A064097(n) - A003313(n).
8

%I #16 Aug 18 2017 09:44:47

%S 0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,1,0,

%T 0,0,0,0,0,0,0,0,1,0,0,1,1,0,1,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,1,1,1,0,

%U 1,0,0,0,0,0,0,0,1,0,0,0,0,0,1,0,0,1,0,0,0,0,0,1,0,1,0,0,0,1,1,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,1,0,0,1,0,0,1,0,0,0,0,0,0,0,2

%N a(n) = A064097(n) - A003313(n).

%C The positions where k = 0, 1, 2, ... occur for the first time are 1, 23, 129, 517, 2049, 4613, 33097, 33793, ... factorized as: 1, 23, 3*43, 11*47, 3*683, 7*659, 23*1439, 47*719, ... - _Antti Karttunen_, Aug 18 2017

%H Antti Karttunen, <a href="/A076142/b076142.txt">Table of n, a(n) for n = 1..10000</a> (also based on the b-file of A003313)

%F It seems that sum(k = 1, n, a(k)) * log(n)/n^2 -> c (0.006 < c < 0.01).

%Y Cf. A003313, A064097, A076091.

%K nonn

%O 1,129

%A _Benoit Cloitre_, Oct 31 2002

%E Extended to 129 terms by _Antti Karttunen_, Aug 18 2017