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%I #6 Dec 05 2013 19:55:46
%S 1,1,2,1,3,2,1,2,4,3,1,5,2,4,3,1,2,3,6,5,4,1,7,2,3,6,5,4,1,2,4,8,7,3,
%T 6,5,1,3,9,2,4,8,7,6,5,1,2,5,10,3,9,4,8,7,6,1,11,2,5,10,3,9,4,8,7,6,1,
%U 2,3,4,6,12,11,5,10,9,8,7,1,13,2,3,4,6,12,11,5,10,9,8,7,1,2,7,14,13,3,4,6
%N Rearrange numbers from 1 to n: start with the divisors of n in ascending order followed by numbers in ascending order which leave a remainder 1 on dividing by n, followed by those leaving remainder 2 ... up to remainder [(n-1)/2].
%C E.g. for n =10 the arrangement is 1,2,5,10,3,9,4,8,7,6.
%e 1; 1,2; 1,3,2; 1,2,4,3; 1,5,2,4,3; 1,2,3,6,5,4; 1,7,2,3,6,5; 1,2,4,8,7,3,6,...
%K nonn
%O 1,3
%A _Amarnath Murthy_, Oct 07 2002
%E More terms from _David Wasserman_, Mar 24 2005
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