%I
%S 1,1,2,2,4,2,4,2,4,6,2,6,4,2,4,6,6,2,6,4,2,6,4,6,8,4,2,4,2,4,14,4,6,2,
%T 10,2,6,6,4,6,6,2,10,2,4,2,12,12,4,2,4,6,2,10,6,6,6,2,6,4,2,10,14,4,2,
%U 4,14,6,10,2,4,6,8,6,6,4,6,8,4,8,10,2,10,2,6,4,6,8,4,2,4,12,8,4,8,4,6
%N A008578(n+2)  A008578(n+1).
%C a(n) = A001223(n) for n>0.
%C n appears this number of times in A000720.  _Lekraj Beedassy_, Jun 19 2006
%C a(0) = 1, for n >= 1: a(n) = differences between consecutive primes (A001223(n)) = A158611(n+2)  A158611(n+1). Partial sums of a(n1) = A006093(n) for n >= 1. [From _Jaroslav Krizek_, Aug 04 2009]
%C First differences of noncomposite numbers. [JuriStepan Gerasimov, Feb 17 2010]
%C This is 1 together with A001223. A054541 is 2 together with A001223. A125266 is 3 together with A001223.  _Omar E. Pol_, Nov 01 2013
%Y Cf. A000040, A075527.
%K nonn
%O 0,3
%A _Reinhard Zumkeller_, Sep 22 2002
%E Correction for change of offset in A158611 and A008578 in Aug 2009 _Jaroslav Krizek_, Jan 27 2010
