%N A008578(n+2) - A008578(n+1).
%C a(n) = A001223(n) for n>0.
%C n appears this number of times in A000720. - _Lekraj Beedassy_, Jun 19 2006
%C a(0) = 1, for n >= 1: a(n) = differences between consecutive primes (A001223(n)) = A158611(n+2) - A158611(n+1). Partial sums of a(n-1) = A006093(n) for n >= 1. [From _Jaroslav Krizek_, Aug 04 2009]
%C First differences of noncomposite numbers. [Juri-Stepan Gerasimov, Feb 17 2010]
%C This is 1 together with A001223. A054541 is 2 together with A001223. A125266 is 3 together with A001223. - _Omar E. Pol_, Nov 01 2013
%Y Cf. A000040, A075527.
%A _Reinhard Zumkeller_, Sep 22 2002
%E Correction for change of offset in A158611 and A008578 in Aug 2009 _Jaroslav Krizek_, Jan 27 2010