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A075254
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a(n) = n + (sum of prime factors of n taken with repetition).
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15
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1, 4, 6, 8, 10, 11, 14, 14, 15, 17, 22, 19, 26, 23, 23, 24, 34, 26, 38, 29, 31, 35, 46, 33, 35, 41, 36, 39, 58, 40, 62, 42, 47, 53, 47, 46, 74, 59, 55, 51, 82, 54, 86, 59, 56, 71, 94, 59, 63, 62, 71, 69, 106, 65, 71, 69, 79, 89, 118, 72, 122, 95, 76, 76, 83, 82, 134, 89, 95, 84, 142
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OFFSET
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1,2
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COMMENTS
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LINKS
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EXAMPLE
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a(6)=11 because 6=2*3, sopfr(6)=2+3=5 and 6+5=11.
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MAPLE
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MATHEMATICA
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Table[If[n==1, 1, n +Plus@@Times@@@FactorInteger@n], {n, 80}] (* G. C. Greubel, Jan 10 2019 *)
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PROG
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(Haskell)
(PARI) a(n) = my(f = factor(n)); n += sum(k=1, #f~, f[k, 1]*f[k, 2]); \\ Michel Marcus, Feb 22 2017
(Magma) [n eq 1 select 1 else (&+[p[1]*p[2]: p in Factorization(n)]) + n: n in [1..80]]; // G. C. Greubel, Jan 10 2019
(Sage) [n + sum(factor(n)[j][0]*factor(n)[j][1] for j in range(0, len(factor(n)))) for n in range(1, 80)] # G. C. Greubel, Jan 10 2019
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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