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1,3
tau(k) < tau(k+1) < ... < tau(k+n-1).
a(11) > 10^12. [From Donovan Johnson, Oct 13 2009]
a(11) > 10^13. - Giovanni Resta, Jul 25 2013
Table of n, a(n) for n=1..10.
a(3) = 61 = a(4) as tau(61)= 2 < tau(62)= 4 < tau(63)=6 < tau(64)=7.
Cf. A075029, A075031.
Sequence in context: A204748 A276471 A122568 * A258158 A042859 A258157
Adjacent sequences: A075025 A075026 A075027 * A075029 A075030 A075031
nonn
Amarnath Murthy, Sep 02 2002
More terms from Antonio G. Astudillo (afg_astudillo(AT)lycos.com), Apr 19 2003
a(7)-a(10) from Donovan Johnson, Oct 13 2009
approved