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1,3

tau(k) < tau(k+1) < ... < tau(k+n-1).

a(11) > 10^12. [From Donovan Johnson, Oct 13 2009]

a(11) > 10^13. - Giovanni Resta, Jul 25 2013

Table of n, a(n) for n=1..10.

a(3) = 61 = a(4) as tau(61)= 2 < tau(62)= 4 < tau(63)=6 < tau(64)=7.

Cf. A075029, A075031.

Sequence in context: A204748 A276471 A122568 * A258158 A042859 A258157

Adjacent sequences: A075025 A075026 A075027 * A075029 A075030 A075031

nonn

Amarnath Murthy, Sep 02 2002

More terms from Antonio G. Astudillo (afg_astudillo(AT)lycos.com), Apr 19 2003

a(7)-a(10) from Donovan Johnson, Oct 13 2009

approved