OFFSET
1,1
COMMENTS
If k is in A065036 tau(k)=omega(k)^3, since k=p^3*q and there are 8 divisors of k: 1, p, q, p^2, p^3, p*q, p^2*q, p^3*q while omega(k)^3=2^3=8
LINKS
Charles R Greathouse IV, Table of n, a(n) for n = 1..10000
PROG
(PARI) is(n)=my(f=factor(n)); numdiv(f)==omega(f)^3 && f[, 2]!=[3, 1]~ && f[, 2]!=[1, 3]~ \\ Charles R Greathouse IV, Oct 16 2015
CROSSREFS
KEYWORD
nonn
AUTHOR
Benoit Cloitre, Sep 10 2002
STATUS
approved