%I #11 Aug 07 2023 08:00:11
%S 7,24,627,1687,10792,376847,1530011,18660269,278567575,1695509434,
%T 11136696004,102111268281,1260654956981,10725187563685,
%U 308788493220129,4193528956200935,25999253094360135,118166387818704584
%N a(n) = floor(1/sin(x(n))) where x(n) is Pi truncated at the n-th decimal digit.
%C a(n+1) = a(n) for n = 31, 49, 53, 64, 70, 76, 84, 96, 105, 115, 120, 127, ...
%F Is there a formula for lim m_{n -> oo} log(a(n))/n >= 2?
%e x(4)=3.1415 and 1/sin(x(4))=10792.889... hence a(4)=10792.
%o (PARI) a(n)=floor(1/sin(floor(Pi*10^n)/10^n))
%K nonn,base
%O 0,1
%A _Benoit Cloitre_, Sep 07 2002