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a(n) = 1^n + 3^n + 8^n.
0

%I #18 Jan 15 2018 03:29:38

%S 3,12,74,540,4178,33012,262874,2099340,16783778,134237412,1073800874,

%T 8590111740,68720008178,549757408212,4398051294074,35184386437740,

%U 281475019757378,2251799942825412,18014398896902474,144115189238117340

%N a(n) = 1^n + 3^n + 8^n.

%H <a href="/index/Rec#order_03">Index entries for linear recurrences with constant coefficients</a>, signature (12,-35,24).

%F From _Mohammad K. Azarian_, Dec 26 2008: (Start)

%F G.f.: 1/(1-x) + 1/(1-3*x) + 1/(1-8*x).

%F E.g.f.: e^x + e^(3*x) + e^(8*x). (End)

%F a(n) = 11*a(n-1) - 24*a(n-2) + 14 with a(0)=3, a(1)=12. - _Vincenzo Librandi_, Jul 21 2010

%t Table[1^n + 3^n + 8^n, {n, 0, 20}]

%Y Cf. A001550, A001576, A034513, A001579, A074501..A074580.

%K easy,nonn

%O 0,1

%A _Robert G. Wilson v_, Aug 23 2002