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a(n) = 1^n + 2^n + 7^n.
0

%I #17 May 21 2019 14:33:42

%S 3,10,54,352,2418,16840,117714,823672,5765058,40354120,282476274,

%T 1977328792,13841291298,96889018600,678223089234,4747561542712,

%U 33232930635138,232630514118280,1628413598172594,11398895185897432

%N a(n) = 1^n + 2^n + 7^n.

%H <a href="/index/Rec">Index entries for linear recurrences with constant coefficients</a>, signature (10,-23,14).

%F From _Mohammad K. Azarian_, Dec 26 2008: (Start)

%F G.f.: 1/(1-x) + 1/(1-2*x) + 1/(1-7*x).

%F E.g.f.: e^x + e^(2*x) + e^(7*x). (End)

%F a(n) = 9*a(n-1) - 14*a(n-2) + 6 with a(0)=3, a(1)=10. - _Vincenzo Librandi_, Jul 21 2010

%t Table[1^n + 2^n + 7^n, {n, 0, 20}]

%t LinearRecurrence[{10,-23,14},{3,10,54},20] (* _Harvey P. Dale_, May 21 2019 *)

%Y Cf. A001550, A001576, A034513, A001579, A074501..A074580.

%K easy,nonn

%O 0,1

%A _Robert G. Wilson v_, Aug 23 2002