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A074023
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Number of elements of GF(7^n) with trace 1 and subtrace 6.
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9
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OFFSET
| 1,2
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COMMENTS
| Same as the number of elements of GF(7^n) with trace 2 and subtrace 3. Same as the number of elements of GF(7^n) with trace 3 and subtrace 5. Same as the number of elements of GF(7^n) with trace 4 and subtrace 5. Same as the number of elements of GF(7^n) with trace 5 and subtrace 3. Same as the number of elements of GF(7^n) with trace 6 and subtrace 6.
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LINKS
| F. Ruskey, Number of Elements of GF(7^n) with given trace and subtrace
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EXAMPLE
| a(3;1,6)=6. Let GF(7^3) be defined by the field extension GF(7)[x]/( 3+b^2+b^3 ). The six elements of GF(7^3) with trace 1 and subtrace 6 are { 1+2b, 2+5b, 1+3b+b^2, 4+5b+b^2, 6+2b+6b^2, 2+4b+6b^2 }.
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CROSSREFS
| Cf. A074014, A074015, A074016, A074017, A074018, A074019, A074020, A074021, A074022.
Sequence in context: A084123 A193473 A181509 * A000146 A167010 A014070
Adjacent sequences: A074020 A074021 A074022 * A074024 A074025 A074026
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KEYWORD
| easy,nonn
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AUTHOR
| Frank Ruskey, Nate Kube (ruskey(AT)cs.uvic.ca), Aug 19 2002
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