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A074013
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Number of elements of GF(5^n) with trace 1 and subtrace 4.
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7
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OFFSET
| 1,3
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COMMENTS
| Same as the number of elements of GF(5^n) with trace 2 and subtrace 1. Same as the number of elements of GF(5^n) with trace 3 and subtrace 1. Same as the number of elements of GF(5^n) with trace 4 and subtrace 4.
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LINKS
| F. Ruskey, Number of Elements of GF(5^n) with given trace and subtrace
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EXAMPLE
| a(3;3,1)=6. Let GF(5^3) be defined by the field extension GF(5)[x]/( 3+2b+3b^2+b^3 ). The six elements of GF(5^3) with trace 3 and subtrace 1 are { 2+b+b^2, 3+2b+b^2, 4+3b+2b^2, 3+2b+3b^2, 4+3b+4b^2, 4b+4b^2 }.
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CROSSREFS
| Cf. A074006, A074007, A074008, A074009, A074010, A074011, A074012.
Sequence in context: A117998 A099840 A074012 * A114959 A000386 A000387
Adjacent sequences: A074010 A074011 A074012 * A074014 A074015 A074016
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KEYWORD
| easy,nonn
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AUTHOR
| Frank Ruskey, Nate Kube (ruskey(AT)cs.uvic.ca), Aug 19 2002
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