|
|
A073728
|
|
a(n) = Sum_{k=0..n} S(k), where S(n) are the tribonacci generalized numbers A001644.
|
|
2
|
|
|
3, 4, 7, 14, 25, 46, 85, 156, 287, 528, 971, 1786, 3285, 6042, 11113, 20440, 37595, 69148, 127183, 233926, 430257, 791366, 1455549, 2677172, 4924087, 9056808, 16658067, 30638962, 56353837, 103650866, 190643665, 350648368, 644942899
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
0,1
|
|
LINKS
|
|
|
FORMULA
|
a(n) = a(n-1) + a(n-2) + a(n-3), a(0)=3, a(1)=4, a(2)=7.
G.f.: (3+x)/(1-x-x^2-x^3).
a(n) = 3*T(n+1) + T(n), where T(n) are the tribonacci numbers A000073.
|
|
MAPLE
|
A:= gfun[rectoproc]({a(n)=a(n-1)+a(n-2)+a(n-3), a(0)=3, a(1)=4, a(2)=7}, a(n), remember):
|
|
MATHEMATICA
|
CoefficientList[Series[(3+x)/(1-x-x^2-x^3), {x, 0, 40}], x]
|
|
PROG
|
(Magma) I:=[3, 4, 7]; [n le 3 select I[n] else Self(n-1)+Self(n-2) +Self(n-3): n in [1..40]]; // Vincenzo Librandi, Mar 27 2015
(PARI) my(x='x+O('x^40)); Vec((3+x)/(1-x-x^2-x^3)) \\ G. C. Greubel, Apr 09 2019
(Sage) ((3+x)/(1-x-x^2-x^3)).series(x, 40).coefficients(x, sparse=False) # G. C. Greubel, Apr 09 2019
|
|
CROSSREFS
|
|
|
KEYWORD
|
easy,nonn
|
|
AUTHOR
|
Mario Catalani (mario.catalani(AT)unito.it), Aug 06 2002
|
|
STATUS
|
approved
|
|
|
|