OFFSET
1,1
FORMULA
a(n) = ceiling((10^n-1)/60) + ceiling((10^n-2)/60) + ceiling((10^n-8)/60) + ceiling((10^n-19)/60) + ceiling((10^n-22)/60) + ceiling((10^n-28)/60) + ceiling((10^n-41)/60) + ceiling((10^n-59)/60).
a(n) = ceiling(40/3*10^(n-1)) for n>1. - Benoit Cloitre, Aug 27 2002; [Edited by Felix Fröhlich, Jun 08 2019]
EXAMPLE
a(2) = 14 because there are 14 Fibonacci numbers up to 10^2 which end in 1.
CROSSREFS
KEYWORD
base,nonn
AUTHOR
Shyam Sunder Gupta, Aug 15 2002
EXTENSIONS
More terms from Vladeta Jovovic, Aug 20 2002
STATUS
approved