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e = 1/a(0)+1/a(1)+1/a(2)+1/a(3)+... with each term a(n) being a positive or negative integer chosen so as to minimize the absolute difference between e and the partial sum.
2

%I #2 Mar 30 2012 18:51:38

%S 1,1,2,5,55,9999,3620211522,-26596490130011501642,

%T 6462025287494698350477135653962718736877,

%U -532695733923048954868620962844302990205269539900643893905567041090276924142488084

%N e = 1/a(0)+1/a(1)+1/a(2)+1/a(3)+... with each term a(n) being a positive or negative integer chosen so as to minimize the absolute difference between e and the partial sum.

%e a(4)=55 since e-(1/1)-(1/1)-(1/2)-(1/5)=0.0182818... is closer to 1/55=0.0181818... than to 1/54=0.0185185...

%Y Cf. A001467, A006525, A014015.

%K sign

%O 0,3

%A _Henry Bottomley_, Jul 30 2002