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Table by antidiagonals of T(n,k)=2n*T(n,k-1)-n^2*T(n,k-2)+T(n,k-4) starting with T(n,1)=1.
2

%I #4 Mar 30 2012 18:51:38

%S 1,2,1,3,4,1,4,12,6,1,6,32,27,8,1,10,81,108,48,10,1,17,200,406,256,75,

%T 12,1,28,488,1470,1281,500,108,14,1,45,1184,5193,6160,3126,864,147,16,

%U 1,72,2865,18036,28832,18770,6481,1372,192,18,1,116,6924,61885,132352

%N Table by antidiagonals of T(n,k)=2n*T(n,k-1)-n^2*T(n,k-2)+T(n,k-4) starting with T(n,1)=1.

%F T(n, k) =(A073133(n, k+2)-A073134(n, k+2))/2 =sum_j{0<=j<=[(k-1)/4]} abs(A053122(k-3j-1, j)*n^(k-4j-1))

%e Rows start: 1,2,3,4,6,10,17,...; 1,4,12,32,81,200,488,...; 1,6,27,108,406,1470,5193,...; 1,8,48,256,1281,6160,28832,...; etc.

%Y Rows include A024490, A048776. Columns include A000012, A005843, A033428, A033430.

%K nonn,tabl

%O 0,2

%A _Henry Bottomley_, Jul 16 2002