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A073128
Integer quotients arising in A063986.
1
0, 1, 1, 5, 5, 49, 118, 121, 2406, 2698, 4182, 4946, 153627, 3087192, 8203485, 38394376, 487844934, 2822741576, 4140154385, 4397137572, 8583966231
OFFSET
1,4
FORMULA
a(n)=Sum[cototient[j], j=1..A063986(n)]/A063986(n)
EXAMPLE
n=15, A063986(15)=41846733, sum of first 41846733 cototients is s=343289046464505, a(15)=s/41846733. Only in knowledge of either the quotients or of partial sums of cototients is it possible to continue A063986 without recomputing previous terms!
KEYWORD
more,nonn
AUTHOR
Labos Elemer, Jul 16 2002
EXTENSIONS
Changed A063896 to A063986 and a(16)-a(21) from Donovan Johnson, May 11 2010
STATUS
approved