1,1

Table of n, a(n) for n=1..72.

Let b(1)=1 b(n+1)=b(n)*floor(n/b(n))+n*floor(b(n)/n) then a(n)=b(n+3)

Table[3*2^(n-1), {n, 1, 5}, {3*2^(n-1)}] // Flatten (* Jean-François Alcover, Nov 24 2016 *)

Sequence in context: A098529 A133774 A108581 * A171601 A057944 A281258

Adjacent sequences: A073077 A073078 A073079 * A073081 A073082 A073083

easy,nonn

Benoit Cloitre, Aug 17 2002

approved