|
| |
|
|
A072967
|
|
Least k>n such that the last digit of k^k is the same as the last digit of n^n.
|
|
0
| |
|
|
11, 18, 17, 6, 15, 8, 13, 12, 19, 20, 21, 14, 27, 16, 25, 24, 23, 22, 29, 30, 31, 38, 37, 26, 35, 28, 33, 32, 39, 40, 41, 34, 47, 36, 45, 44, 43, 42, 49, 50, 51, 58, 57, 46, 55, 48, 53, 52, 59, 60, 61, 54, 67, 56, 65, 64, 63, 62, 69, 70, 71, 78, 77, 66, 75, 68, 73, 72, 79, 80
(list; graph; refs; listen; history; internal format)
|
|
|
|
OFFSET
| 1,1
|
|
|
FORMULA
| a(n)=n+b(n) where b(n) is a periodic sequence with period (10, 16, 14, 2, 10, 2, 6, 4, 10, 10, 10, 2, 14, 2, 10, 8, 6, 4, 10, 10, 10) of length 21
|
|
|
PROG
| (PARI) a(n)=if(n<0, 0, s=n+1; while(abs(s^s%10-n^n%10)>0, s++); s)
|
|
|
CROSSREFS
| Sequence in context: A078874 A162555 A059141 * A054306 A093519 A031119
Adjacent sequences: A072964 A072965 A072966 * A072968 A072969 A072970
|
|
|
KEYWORD
| base,easy,nonn
|
|
|
AUTHOR
| Benoit Cloitre (benoit7848c(AT)orange.fr), Aug 13 2002
|
| |
|
|
