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A072841
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Numbers n such that the integer digits of n^2 are exactly the same (albeit in different order) as the integer digits of (n+1)^2.
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4
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13, 157, 913, 4513, 14647, 19201, 19291, 19813, 20191, 27778, 31828, 34825, 37471, 39586, 40297, 50386, 53536, 53842, 54913, 62986, 64021, 70267, 76513, 78241, 82597, 89356, 98347, 100147, 100597, 103909, 106528, 111847, 115024, 117391, 125986, 128047
(list; graph; refs; listen; history; internal format)
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OFFSET
| 1,1
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COMMENTS
| All terms are of form 9k+4. [From Zak Seidov (zakseidov(AT)yahoo.com), Jun 04 2010]
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REFERENCES
| Boris A. Kordemsky, The Moscow Puzzles, p. 165 (1972).
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LINKS
| Zak Seidov, Table of n, a(n) for n = 1..519 [From Zak Seidov (zakseidov(AT)yahoo.com), Jun 04 2010]
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EXAMPLE
| 913 is included because 913^2 = 833569, 914^2 = 835396 and both 833569 and 835396 contain exactly the same integer digits.
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MATHEMATICA
| okQ[n_] := Module[{idn = IntegerDigits[n^2]}, Sort[idn] == Sort[IntegerDigits[(n + 1)^2]]]; Select[Range[100000], okQ]
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CROSSREFS
| Sequence in context: A130868 A154414 A164623 * A159499 A125470 A165151
Adjacent sequences: A072838 A072839 A072840 * A072842 A072843 A072844
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KEYWORD
| nonn,base
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AUTHOR
| Harvey P. Dale (hpd1(AT)nyu.edu), Aug 09 2002
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EXTENSIONS
| Terms from 100147 on from N. J. A. Sloane, May 24 2010
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