A072515 Let u(1) = u(2) = v(1) = v(2) = 1, u(n+2) = u(n+1)+v(n), v(n+2) = abs(u(n+1)-v(n)), then a(n) = u(n).

1, 1, 2, 1, 3, 2, 3, 5, 4, 7, 7, 8, 13, 9, 20, 15, 23, 32, 25, 53, 36, 67, 75, 70, 139, 81, 198, 161, 199, 358, 235, 521, 430, 561, 911, 612, 1421, 1013, 1632, 2223, 1829, 3658, 2617, 4699, 5234, 4699, 9933, 5234, 14097, 11003, 14632, 24565, 17191, 36638

Offset

1,3

Comments

For any initial values u(1), v(1), u(2), v(2), it seems that lim n ->infinity log(a(n))/n = C = 0.192...

Links

Table of n, a(n) for n=1..54.

Crossrefs

Sequence in context: A183163 A338359 A122545 * A318747 A297367 A118010

Adjacent sequences: A072512 A072513 A072514 * A072516 A072517 A072518

Keyword

easy,nonn

Author

Benoit Cloitre, Aug 04 2002

Status

approved