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A072355
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Numbers k such that sigma(k) = (Pi^2)*(k/6) rounded off (where 0.5 is rounded to 0).
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3
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2, 4, 22, 63, 4202, 4246, 444886, 1161238, 9362914, 26996486, 545614671, 1640386293, 2242930954, 2243031802, 2243065418, 2243115842, 18000691527
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OFFSET
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1,1
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COMMENTS
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In 1838 Dirichlet showed that the average value of sigma(n) is (Pi^2)*(n/6) for large n (see Tattersall).
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REFERENCES
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Tattersall, J. "Elementary Number Theory in Nine Chapters", Cambridge University Press, 1999.
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LINKS
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EXAMPLE
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sigma(444886) = 731808 = (Pi^2 * 444886)/6 rounded off; so 444886 is a term of the sequence.
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MATHEMATICA
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Select[Range[10^6], Round[(Pi^2 * #)/6] == DivisorSigma[1, # ] &]
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CROSSREFS
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KEYWORD
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nonn,more
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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