%I #12 Jul 13 2021 02:00:32
%S 1,3,8,9,14,15,22,44,45,52,63,64,105,110,130,152,154,165,174,184,189,
%T 190,195,196,208,225,230,232,256,272,310,405,442,464,496,512,567,592,
%U 656,688,820,884,891,940,976,1036,1068,1125,1148,1210,1215,1284,1305
%N Numbers k such that the number of divisors of k equals the maximum number of elements among the continued fractions for k/1, k/2, k/3, k/4, ..., k/k.
%o (PARI) for(n=1,1000, if( numdiv(n) == vecmax( vector(n,i,length(contfrac(n/i)))), print1(n,",")));
%K easy,nonn
%O 1,2
%A _Benoit Cloitre_, Jun 22 2002