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Numbers k such that the number of divisors of k equals the maximum number of elements among the continued fractions for k/1, k/2, k/3, k/4, ..., k/k.
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%I #12 Jul 13 2021 02:00:32

%S 1,3,8,9,14,15,22,44,45,52,63,64,105,110,130,152,154,165,174,184,189,

%T 190,195,196,208,225,230,232,256,272,310,405,442,464,496,512,567,592,

%U 656,688,820,884,891,940,976,1036,1068,1125,1148,1210,1215,1284,1305

%N Numbers k such that the number of divisors of k equals the maximum number of elements among the continued fractions for k/1, k/2, k/3, k/4, ..., k/k.

%o (PARI) for(n=1,1000, if( numdiv(n) == vecmax( vector(n,i,length(contfrac(n/i)))), print1(n,",")));

%K easy,nonn

%O 1,2

%A _Benoit Cloitre_, Jun 22 2002